Base | Representation |
---|---|
bin | 1011000001100110010110… |
… | …0101011011111101111011 |
3 | 1120220212021010120111101222 |
4 | 2300121211211123331323 |
5 | 3042102031104201021 |
6 | 41440452232102255 |
7 | 2360535663042662 |
oct | 260314545337573 |
9 | 46825233514358 |
10 | 12122102022011 |
11 | 3953a556291a3 |
12 | 143941753498b |
13 | 69c156222257 |
14 | 2dc9da179dd9 |
15 | 1604cc6dc6ab |
hex | b066595bf7b |
12122102022011 has 2 divisors, whose sum is σ = 12122102022012. Its totient is φ = 12122102022010.
The previous prime is 12122102021983. The next prime is 12122102022013. The reversal of 12122102022011 is 11022020122121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12122102022011 - 214 = 12122102005627 is a prime.
Together with 12122102022013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12122102022013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061051011005 + 6061051011006.
It is an arithmetic number, because the mean of its divisors is an integer number (6061051011006).
Almost surely, 212122102022011 is an apocalyptic number.
12122102022011 is a deficient number, since it is larger than the sum of its proper divisors (1).
12122102022011 is an equidigital number, since it uses as much as digits as its factorization.
12122102022011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 12122102022011 its reverse (11022020122121), we get a palindrome (23144122144132).
The spelling of 12122102022011 in words is "twelve trillion, one hundred twenty-two billion, one hundred two million, twenty-two thousand, eleven".
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