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12122411300 = 2252121224113
BaseRepresentation
bin10110100101000110…
…10101000100100100
31011021211110022002022
423102203111010210
5144311314130200
65322521202312
7606255536666
oct132243250444
934254408068
1012122411300
11516087003a
122423930398
1311b262414c
1482dda4536
154ae3a0885
hex2d28d5124

12122411300 has 18 divisors (see below), whose sum is σ = 26305632738. Its totient is φ = 4848964480.

The previous prime is 12122411297. The next prime is 12122411309. The reversal of 12122411300 is 311422121.

It can be written as a sum of positive squares in 3 ways, for example, as 115949824 + 12006461476 = 10768^2 + 109574^2 .

It is not an unprimeable number, because it can be changed into a prime (12122411309) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 60611957 + ... + 60612156.

It is an arithmetic number, because the mean of its divisors is an integer number (1461424041).

Almost surely, 212122411300 is an apocalyptic number.

12122411300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

12122411300 is an abundant number, since it is smaller than the sum of its proper divisors (14183221438).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12122411300 is a wasteful number, since it uses less digits than its factorization.

12122411300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 121224127 (or 121224120 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 12122411300 its reverse (311422121), we get a palindrome (12433833421).

The spelling of 12122411300 in words is "twelve billion, one hundred twenty-two million, four hundred eleven thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 121224113 242448226 484896452 606120565 1212241130 2424482260 3030602825 6061205650 12122411300