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121230542597 is a prime number
BaseRepresentation
bin111000011100111100…
…1110100011100000101
3102120220202122122121012
41300321321310130011
53441240004330342
6131405331132005
711521130416103
oct1607171643405
9376822578535
10121230542597
1147460531a7a
121b5b3a44005
13b580113798
145c20946c73
153248025b82
hex1c39e74705

121230542597 has 2 divisors, whose sum is σ = 121230542598. Its totient is φ = 121230542596.

The previous prime is 121230542593. The next prime is 121230542633. The reversal of 121230542597 is 795245032121.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 103240758721 + 17989783876 = 321311^2 + 134126^2 .

It is a cyclic number.

It is not a de Polignac number, because 121230542597 - 22 = 121230542593 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121230542593) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60615271298 + 60615271299.

It is an arithmetic number, because the mean of its divisors is an integer number (60615271299).

Almost surely, 2121230542597 is an apocalyptic number.

It is an amenable number.

121230542597 is a deficient number, since it is larger than the sum of its proper divisors (1).

121230542597 is an equidigital number, since it uses as much as digits as its factorization.

121230542597 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151200, while the sum is 41.

The spelling of 121230542597 in words is "one hundred twenty-one billion, two hundred thirty million, five hundred forty-two thousand, five hundred ninety-seven".