1212412114013 has 2 divisors, whose sum is σ = 1212412114014. Its totient is φ = 1212412114012.

The previous prime is 1212412114009. The next prime is 1212412114031. The reversal of 1212412114013 is 3104112142121.

Together with next prime (1212412114031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1209201531769 + 3210582244 = 1099637^2 + 56662^2 .

It is a cyclic number.

It is not a de Polignac number, because 1212412114013 - 2² = 1212412114009 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1212412114013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1212412114063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606206057006 + 606206057007.

It is an arithmetic number, because the mean of its divisors is an integer number (606206057007).

Almost surely, 2^{1212412114013} is an apocalyptic number.

It is an amenable number.

1212412114013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1212412114013 is an equidigital number, since it uses as much as digits as its factorization.

1212412114013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 1212412114013 its reverse (3104112142121), we get a palindrome (4316524256134).

The spelling of 1212412114013 in words is "one trillion, two hundred twelve billion, four hundred twelve million, one hundred fourteen thousand, thirteen".