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121243314341 is a prime number
BaseRepresentation
bin111000011101010101…
…0100010100010100101
3102120221122200112010202
41300322222202202211
53441301242024331
6131410505000245
711521344111362
oct1607252424245
9376848615122
10121243314341
1147467765636
121b5b8183085
13b582965b26
145c2250d469
1532491e9ecb
hex1c3aaa28a5

121243314341 has 2 divisors, whose sum is σ = 121243314342. Its totient is φ = 121243314340.

The previous prime is 121243314329. The next prime is 121243314377. The reversal of 121243314341 is 143413342121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121180572100 + 62742241 = 348110^2 + 7921^2 .

It is a cyclic number.

It is not a de Polignac number, because 121243314341 - 214 = 121243297957 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121243314391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60621657170 + 60621657171.

It is an arithmetic number, because the mean of its divisors is an integer number (60621657171).

Almost surely, 2121243314341 is an apocalyptic number.

It is an amenable number.

121243314341 is a deficient number, since it is larger than the sum of its proper divisors (1).

121243314341 is an equidigital number, since it uses as much as digits as its factorization.

121243314341 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6912, while the sum is 29.

Adding to 121243314341 its reverse (143413342121), we get a palindrome (264656656462).

The spelling of 121243314341 in words is "one hundred twenty-one billion, two hundred forty-three million, three hundred fourteen thousand, three hundred forty-one".