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12127085567 is a prime number
BaseRepresentation
bin10110100101101010…
…01010001111111111
31011022011020202222022
423102311022033333
5144314013214232
65323205310355
7606343345412
oct132265121777
934264222868
1012127085567
115163472973
1224254053bb
1311b359c89c
1483085db79
154ae9c5812
hex2d2d4a3ff

12127085567 has 2 divisors, whose sum is σ = 12127085568. Its totient is φ = 12127085566.

The previous prime is 12127085489. The next prime is 12127085569. The reversal of 12127085567 is 76558072121.

It is a strong prime.

It is an emirp because it is prime and its reverse (76558072121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12127085567 - 232 = 7832118271 is a prime.

It is a super-3 number, since 3×121270855673 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 12127085569, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12127085569) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6063542783 + 6063542784.

It is an arithmetic number, because the mean of its divisors is an integer number (6063542784).

Almost surely, 212127085567 is an apocalyptic number.

12127085567 is a deficient number, since it is larger than the sum of its proper divisors (1).

12127085567 is an equidigital number, since it uses as much as digits as its factorization.

12127085567 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 235200, while the sum is 44.

The spelling of 12127085567 in words is "twelve billion, one hundred twenty-seven million, eighty-five thousand, five hundred sixty-seven".