Base | Representation |
---|---|
bin | 11011100101001001011011… |
… | …100010011100100011001000 |
3 | 120220111011111201010201010221 |
4 | 123211021123202130203020 |
5 | 111344334401021130440 |
6 | 1105552241322115424 |
7 | 34356431063030032 |
oct | 3345113342344310 |
9 | 526434451121127 |
10 | 121300002130120 |
11 | 35717050a10830 |
12 | 1173090534bb74 |
13 | 528b705abb828 |
14 | 21d4d46a10c52 |
15 | e0545884bd4a |
hex | 6e525b89c8c8 |
121300002130120 has 192 divisors, whose sum is σ = 315154305083520. Its totient is φ = 41645084544000.
The previous prime is 121300002130091. The next prime is 121300002130141. The reversal of 121300002130120 is 21031200003121.
It is a super-3 number, since 3×1213000021301203 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 121300002130094 and 121300002130103.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 13838029 + ... + 20834851.
It is an arithmetic number, because the mean of its divisors is an integer number (1641428672310).
Almost surely, 2121300002130120 is an apocalyptic number.
121300002130120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 121300002130120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (157577152541760).
121300002130120 is an abundant number, since it is smaller than the sum of its proper divisors (193854302953400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121300002130120 is a wasteful number, since it uses less digits than its factorization.
121300002130120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6996948 (or 6996913 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 121300002130120 its reverse (21031200003121), we get a palindrome (142331202133241).
The spelling of 121300002130120 in words is "one hundred twenty-one trillion, three hundred billion, two million, one hundred thirty thousand, one hundred twenty".
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