121300312001220 has 864 divisors, whose sum is σ = 431378698173696. Its totient is φ = 27354743193600.

The previous prime is 121300312001213. The next prime is 121300312001233. The reversal of 121300312001220 is 22100213003121.

121300312001220 is a `hidden beast` number, since 1 + 2 + 130 + 0 + 312 + 0 + 0 + 1 + 220 = 666.

121300312001220 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×121300312001220² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 121300312001193 and 121300312001202.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 17296490434 + ... + 17296497446.

It is an arithmetic number, because the mean of its divisors is an integer number (499280900664).

Almost surely, 2^{121300312001220} is an apocalyptic number.

121300312001220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 121300312001220, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (215689349086848).

121300312001220 is an abundant number, since it is smaller than the sum of its proper divisors (310078386172476).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121300312001220 is a wasteful number, since it uses less digits than its factorization.

121300312001220 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7421 (or 7399 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 121300312001220 its reverse (22100213003121), we get a palindrome (143400525004341).

The spelling of 121300312001220 in words is "one hundred twenty-one trillion, three hundred billion, three hundred twelve million, one thousand, two hundred twenty".