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1213004003 is a prime number
BaseRepresentation
bin100100001001100…
…1111100011100011
310010112110222200012
41020103033203203
54441012112003
6320210515135
742026235551
oct11023174343
93115428605
101213004003
11572788952
1229a295aab
131643c8463
14b7156bd1
15717588d8
hex484cf8e3

1213004003 has 2 divisors, whose sum is σ = 1213004004. Its totient is φ = 1213004002.

The previous prime is 1213003997. The next prime is 1213004017. The reversal of 1213004003 is 3004003121.

It is an a-pointer prime, because the next prime (1213004017) can be obtained adding 1213004003 to its sum of digits (14).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1213004003 is a prime.

It is a super-2 number, since 2×12130040032 = 2942757422588048018, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1213004033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606502001 + 606502002.

It is an arithmetic number, because the mean of its divisors is an integer number (606502002).

Almost surely, 21213004003 is an apocalyptic number.

1213004003 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213004003 is an equidigital number, since it uses as much as digits as its factorization.

1213004003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 14.

The square root of 1213004003 is about 34828.2070023709. The cubic root of 1213004003 is about 1066.4833461108.

Adding to 1213004003 its reverse (3004003121), we get a palindrome (4217007124).

It can be divided in two parts, 121 and 3004003, that multiplied together give a palindrome (363484363).

The spelling of 1213004003 in words is "one billion, two hundred thirteen million, four thousand, three".