Base | Representation |
---|---|
bin | 10110100110000000… |
… | …11011110010100111 |
3 | 1011022100210221001202 |
4 | 23103000123302213 |
5 | 144320242302444 |
6 | 5323352513115 |
7 | 606410435006 |
oct | 132300336247 |
9 | 34270727052 |
10 | 12130040999 |
11 | 516510137a |
12 | 24263ab79b |
13 | 11b4095b6b |
14 | 830dccc3d |
15 | 4aedab34e |
hex | 2d301bca7 |
12130040999 has 2 divisors, whose sum is σ = 12130041000. Its totient is φ = 12130040998.
The previous prime is 12130040977. The next prime is 12130041031. The reversal of 12130040999 is 99904003121.
12130040999 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12130040999 - 216 = 12129975463 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12130040939) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6065020499 + 6065020500.
It is an arithmetic number, because the mean of its divisors is an integer number (6065020500).
Almost surely, 212130040999 is an apocalyptic number.
12130040999 is a deficient number, since it is larger than the sum of its proper divisors (1).
12130040999 is an equidigital number, since it uses as much as digits as its factorization.
12130040999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17496, while the sum is 38.
The spelling of 12130040999 in words is "twelve billion, one hundred thirty million, forty thousand, nine hundred ninety-nine".
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