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121301010403 = 1011201000103
BaseRepresentation
bin111000011111000011…
…0101000011111100011
3102121002200020210020221
41300332012220133203
53441411024313103
6131420325343511
711522644401436
oct1607606503743
9377080223227
10121301010403
1147497292531
121b613567b97
13b5918b7201
145c2a04b81d
15324e2e51bd
hex1c3e1a87e3

121301010403 has 4 divisors (see below), whose sum is σ = 122502010608. Its totient is φ = 120100010200.

The previous prime is 121301010373. The next prime is 121301010487. The reversal of 121301010403 is 304010103121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 121301010403 - 229 = 120764139491 is a prime.

It is a super-4 number, since 4×1213010104034 (a number of 45 digits) contains 4444 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121301014403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 600499951 + ... + 600500152.

It is an arithmetic number, because the mean of its divisors is an integer number (30625502652).

Almost surely, 2121301010403 is an apocalyptic number.

121301010403 is a deficient number, since it is larger than the sum of its proper divisors (1201000205).

121301010403 is a wasteful number, since it uses less digits than its factorization.

121301010403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1201000204.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 121301010403 its reverse (304010103121), we get a palindrome (425311113524).

The spelling of 121301010403 in words is "one hundred twenty-one billion, three hundred one million, ten thousand, four hundred three".

Divisors: 1 101 1201000103 121301010403