12130101212535 has 48 divisors (see below), whose sum is σ = 21543368884128. Its totient is φ = 6310119628800.

The previous prime is 12130101212513. The next prime is 12130101212543. The reversal of 12130101212535 is 53521210103121.

12130101212535 is a `hidden beast` number, since 1 + 2 + 1 + 3 + 0 + 1 + 0 + 121 + 2 + 535 = 666.

It is not a de Polignac number, because 12130101212535 - 2⁸ = 12130101212279 is a prime.

It is a super-2 number, since 2×12130101212535² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12130101212499 and 12130101212508.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 7134615 + ... + 8669655.

It is an arithmetic number, because the mean of its divisors is an integer number (448820185086).

Almost surely, 2^{12130101212535} is an apocalyptic number.

12130101212535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

12130101212535 is a deficient number, since it is larger than the sum of its proper divisors (9413267671593).

12130101212535 is a wasteful number, since it uses less digits than its factorization.

12130101212535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1539376 (or 1539373 counting only the distinct ones).

The product of its (nonzero) digits is 1800, while the sum is 27.

Adding to 12130101212535 its reverse (53521210103121), we get a palindrome (65651311315656).

The spelling of 12130101212535 in words is "twelve trillion, one hundred thirty billion, one hundred one million, two hundred twelve thousand, five hundred thirty-five".