12130434433 has 4 divisors (see below), whose sum is σ = 13063544788. Its totient is φ = 11197324080.

The previous prime is 12130434431. The next prime is 12130434457. The reversal of 12130434433 is 33443403121.

12130434433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33443403121 = 28661 ⋅1166861.

It can be written as a sum of positive squares in 2 ways, for example, as 494929009 + 11635505424 = 22247^2 + 107868^2 .

It is a cyclic number.

It is not a de Polignac number, because 12130434433 - 2¹ = 12130434431 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12130434431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 466555158 + ... + 466555183.

It is an arithmetic number, because the mean of its divisors is an integer number (3265886197).

Almost surely, 2^12130434433 is an apocalyptic number.

12130434433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

12130434433 is a deficient number, since it is larger than the sum of its proper divisors (933110355).

12130434433 is an equidigital number, since it uses as much as digits as its factorization.

12130434433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 933110354.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 12130434433 its reverse (33443403121), we get a palindrome (45573837554).

The spelling of 12130434433 in words is "twelve billion, one hundred thirty million, four hundred thirty-four thousand, four hundred thirty-three".