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121310013000 = 233531137731361
BaseRepresentation
bin111000011111010100…
…0111110011001001000
3102121010022012011111110
41300332220332121020
53441420330404000
6131421250330320
711523114045201
oct1607650763110
9377108164443
10121310013000
11474a13812a0
121b6165899a0
13b593719aa7
145c2b3125a8
15324eec2850
hex1c3ea3e648

121310013000 has 512 divisors, whose sum is σ = 430179310080. Its totient is φ = 28200960000.

The previous prime is 121310012977. The next prime is 121310013007. The reversal of 121310013000 is 310013121.

It is a super-2 number, since 2×1213100130002 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is not an unprimeable number, because it can be changed into a prime (121310013007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 89132320 + ... + 89133680.

It is an arithmetic number, because the mean of its divisors is an integer number (840193965).

Almost surely, 2121310013000 is an apocalyptic number.

121310013000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 121310013000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (215089655040).

121310013000 is an abundant number, since it is smaller than the sum of its proper divisors (308869297080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121310013000 is a wasteful number, since it uses less digits than its factorization.

121310013000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1506 (or 1492 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 121310013000 its reverse (310013121), we get a palindrome (121620026121).

The spelling of 121310013000 in words is "one hundred twenty-one billion, three hundred ten million, thirteen thousand".