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121310013001 = 160175771401
BaseRepresentation
bin111000011111010100…
…0111110011001001001
3102121010022012011111111
41300332220332121021
53441420330404001
6131421250330321
711523114045202
oct1607650763111
9377108164444
10121310013001
11474a13812a1
121b6165899a1
13b593719aa8
145c2b3125a9
15324eec2851
hex1c3ea3e649

121310013001 has 4 divisors (see below), whose sum is σ = 121385786004. Its totient is φ = 121234240000.

The previous prime is 121310012977. The next prime is 121310013007. The reversal of 121310013001 is 100310013121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 87343891600 + 33966121401 = 295540^2 + 184299^2 .

It is a cyclic number.

It is not a de Polignac number, because 121310013001 - 25 = 121310012969 is a prime.

It is a super-2 number, since 2×1213100130012 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121310013007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37884100 + ... + 37887301.

It is an arithmetic number, because the mean of its divisors is an integer number (30346446501).

Almost surely, 2121310013001 is an apocalyptic number.

It is an amenable number.

121310013001 is a deficient number, since it is larger than the sum of its proper divisors (75773003).

121310013001 is an equidigital number, since it uses as much as digits as its factorization.

121310013001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 75773002.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 121310013001 its reverse (100310013121), we get a palindrome (221620026122).

The spelling of 121310013001 in words is "one hundred twenty-one billion, three hundred ten million, thirteen thousand, one".

Divisors: 1 1601 75771401 121310013001