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1213100222333 is a prime number
BaseRepresentation
bin10001101001110010011…
…010000110011101111101
311021222020001002100122012
4101221302122012131331
5124333412124103313
62325142431501005
7153433516520036
oct21516232063575
94258201070565
101213100222333
114285224a501a
12177134987765
138a51967a45c
1442a00301a8d
152184ed37da8
hex11a7268677d

1213100222333 has 2 divisors, whose sum is σ = 1213100222334. Its totient is φ = 1213100222332.

The previous prime is 1213100222237. The next prime is 1213100222377. The reversal of 1213100222333 is 3332220013121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 952941058969 + 260159163364 = 976187^2 + 510058^2 .

It is a cyclic number.

It is not a de Polignac number, because 1213100222333 - 216 = 1213100156797 is a prime.

It is a super-2 number, since 2×12131002223332 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1213100222299 and 1213100222308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1213100224333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606550111166 + 606550111167.

It is an arithmetic number, because the mean of its divisors is an integer number (606550111167).

Almost surely, 21213100222333 is an apocalyptic number.

It is an amenable number.

1213100222333 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213100222333 is an equidigital number, since it uses as much as digits as its factorization.

1213100222333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 1213100222333 its reverse (3332220013121), we get a palindrome (4545320235454).

The spelling of 1213100222333 in words is "one trillion, two hundred thirteen billion, one hundred million, two hundred twenty-two thousand, three hundred thirty-three".