121310103012221 has 2 divisors, whose sum is σ = 121310103012222. Its totient is φ = 121310103012220.

The previous prime is 121310103012169. The next prime is 121310103012223. The reversal of 121310103012221 is 122210301013121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 103448956212196 + 17861146800025 = 10170986^2 + 4226245^2 .

It is an emirp because it is prime and its reverse (122210301013121) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-121310103012221 is a prime.

It is a super-2 number, since 2×121310103012221² (a number of 29 digits) contains 22 as substring.

Together with 121310103012223, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 121310103012193 and 121310103012202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121310103012223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60655051506110 + 60655051506111.

It is an arithmetic number, because the mean of its divisors is an integer number (60655051506111).

Almost surely, 2^{121310103012221} is an apocalyptic number.

It is an amenable number.

121310103012221 is a deficient number, since it is larger than the sum of its proper divisors (1).

121310103012221 is an equidigital number, since it uses as much as digits as its factorization.

121310103012221 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 121310103012221 its reverse (122210301013121), we get a palindrome (243520404025342).

The spelling of 121310103012221 in words is "one hundred twenty-one trillion, three hundred ten billion, one hundred three million, twelve thousand, two hundred twenty-one".