121310113 has 4 divisors (see below), whose sum is σ = 128446020. Its totient is φ = 114174208.

The previous prime is 121310107. The next prime is 121310141. The reversal of 121310113 is 311013121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311013121 = 353 ⋅881057.

It can be written as a sum of positive squares in 2 ways, for example, as 62204769 + 59105344 = 7887^2 + 7688^2 .

It is a cyclic number.

It is not a de Polignac number, because 121310113 - 2⁵ = 121310081 is a prime.

It is a super-2 number, since 2×121310113² = 29432287032145538, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121310093 and 121310102.

It is not an unprimeable number, because it can be changed into a prime (121317113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3567928 + ... + 3567961.

It is an arithmetic number, because the mean of its divisors is an integer number (32111505).

Almost surely, 2^121310113 is an apocalyptic number.

It is an amenable number.

121310113 is a deficient number, since it is larger than the sum of its proper divisors (7135907).

121310113 is an equidigital number, since it uses as much as digits as its factorization.

121310113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7135906.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 121310113 is about 11014.0870252600. The cubic root of 121310113 is about 495.0309309652.

Adding to 121310113 its reverse (311013121), we get a palindrome (432323234).

The spelling of 121310113 in words is "one hundred twenty-one million, three hundred ten thousand, one hundred thirteen".