Search a number
-
+
12132030111012 = 22337232293046831
BaseRepresentation
bin1011000010001011010101…
…0110000101110100100100
31120221210220001000200012000
42300202311112011310210
53042232344202023022
641445213325325300
72361340005311610
oct260426526056444
946853801020160
1012132030111012
11395818a797429
12143b328406830
136a0079052126
142dd29c940340
151608ae0e36ac
hexb08b5585d24

12132030111012 has 192 divisors, whose sum is σ = 37673468313600. Its totient is φ = 3301106244480.

The previous prime is 12132030110957. The next prime is 12132030111031. The reversal of 12132030111012 is 21011103023121.

12132030111012 is a `hidden beast` number, since 1 + 21 + 320 + 301 + 1 + 10 + 12 = 666.

It is a super-2 number, since 2×121320301110122 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2458437 + ... + 5505267.

It is an arithmetic number, because the mean of its divisors is an integer number (196215980800).

Almost surely, 212132030111012 is an apocalyptic number.

12132030111012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12132030111012, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18836734156800).

12132030111012 is an abundant number, since it is smaller than the sum of its proper divisors (25541438202588).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12132030111012 is a wasteful number, since it uses less digits than its factorization.

12132030111012 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3047103 (or 3047095 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 12132030111012 its reverse (21011103023121), we get a palindrome (33143133134133).

The spelling of 12132030111012 in words is "twelve trillion, one hundred thirty-two billion, thirty million, one hundred eleven thousand, twelve".