Base | Representation |
---|---|
bin | 10110100110010000… |
… | …00100100100000011 |
3 | 1011022111120122022100 |
4 | 23103020010210003 |
5 | 144321300334021 |
6 | 5323503441443 |
7 | 606433443534 |
oct | 132310044403 |
9 | 34274518270 |
10 | 12132043011 |
11 | 5166249530 |
12 | 2426bb6283 |
13 | 11b461719a |
14 | 83139068b |
15 | 4b0154626 |
hex | 2d3204903 |
12132043011 has 24 divisors (see below), whose sum is σ = 19430564400. Its totient is φ = 7232212800.
The previous prime is 12132043009. The next prime is 12132043051. The reversal of 12132043011 is 11034023121.
12132043011 is a `hidden beast` number, since 1 + 213 + 20 + 430 + 1 + 1 = 666.
It is not a de Polignac number, because 12132043011 - 21 = 12132043009 is a prime.
It is a super-2 number, since 2×121320430112 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (12132043051) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 998436 + ... + 1010513.
It is an arithmetic number, because the mean of its divisors is an integer number (809606850).
Almost surely, 212132043011 is an apocalyptic number.
12132043011 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
12132043011 is a deficient number, since it is larger than the sum of its proper divisors (7298521389).
12132043011 is a wasteful number, since it uses less digits than its factorization.
12132043011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2009027 (or 2009024 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 12132043011 its reverse (11034023121), we get a palindrome (23166066132).
The spelling of 12132043011 in words is "twelve billion, one hundred thirty-two million, forty-three thousand, eleven".
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