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12132122130000 = 243254499270143
BaseRepresentation
bin1011000010001011101011…
…0101000111011001010000
31120221211010110011201111200
42300202322311013121100
53042233041231130000
641445230413511200
72361342203413545
oct260427265073120
946854113151450
1012132122130000
113958227727684
12143b3531a2500
136a0092130032
142dd2aac54bcc
151608b721d500
hexb08bad47650

12132122130000 has 300 divisors, whose sum is σ = 42512966496000. Its totient is φ = 3228737184000.

The previous prime is 12132122129983. The next prime is 12132122130061. The reversal of 12132122130000 is 3122123121.

12132122130000 is a `hidden beast` number, since 1 + 21 + 321 + 2 + 21 + 300 + 0 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (300).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 44774929 + ... + 45045071.

It is an arithmetic number, because the mean of its divisors is an integer number (141709888320).

Almost surely, 212132122130000 is an apocalyptic number.

12132122130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12132122130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21256483248000).

12132122130000 is an abundant number, since it is smaller than the sum of its proper divisors (30380844366000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12132122130000 is a wasteful number, since it uses less digits than its factorization.

12132122130000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 270676 (or 270652 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 12132122130000 its reverse (3122123121), we get a palindrome (12135244253121).

The spelling of 12132122130000 in words is "twelve trillion, one hundred thirty-two billion, one hundred twenty-two million, one hundred thirty thousand".