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12132251335 = 52426450267
BaseRepresentation
bin10110100110010001…
…10111011011000111
31011022111222020002001
423103020313123013
5144321324020320
65323512130131
7606435302101
oct132310673307
934274866061
1012132251335
115166380aa6
122427096947
1311b468ac59
14831406571
154b019620a
hex2d32376c7

12132251335 has 4 divisors (see below), whose sum is σ = 14558701608. Its totient is φ = 9705801064.

The previous prime is 12132251321. The next prime is 12132251363. The reversal of 12132251335 is 53315223121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53315223121 = 57191932231.

It is a cyclic number.

It is not a de Polignac number, because 12132251335 - 211 = 12132249287 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1213225129 + ... + 1213225138.

It is an arithmetic number, because the mean of its divisors is an integer number (3639675402).

Almost surely, 212132251335 is an apocalyptic number.

12132251335 is a deficient number, since it is larger than the sum of its proper divisors (2426450273).

12132251335 is an equidigital number, since it uses as much as digits as its factorization.

12132251335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2426450272.

The product of its digits is 5400, while the sum is 28.

Adding to 12132251335 its reverse (53315223121), we get a palindrome (65447474456).

The spelling of 12132251335 in words is "twelve billion, one hundred thirty-two million, two hundred fifty-one thousand, three hundred thirty-five".

Divisors: 1 5 2426450267 12132251335