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12132441433 = 714591187941
BaseRepresentation
bin10110100110010011…
…00101110101011001
31011022112022212211201
423103021211311121
5144321401111213
65323520154201
7606440023240
oct132311456531
934275285751
1012132441433
1151664a0902
122427168961
1311b4726638
14831455957
154b01d26dd
hex2d3265d59

12132441433 has 8 divisors (see below), whose sum is σ = 13875162560. Its totient is φ = 10392099120.

The previous prime is 12132441427. The next prime is 12132441457. The reversal of 12132441433 is 33414423121.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12132441433 - 25 = 12132441401 is a prime.

It is a super-2 number, since 2×121324414332 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (12132445433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 583758 + ... + 604183.

It is an arithmetic number, because the mean of its divisors is an integer number (1734395320).

Almost surely, 212132441433 is an apocalyptic number.

It is an amenable number.

12132441433 is a deficient number, since it is larger than the sum of its proper divisors (1742721127).

12132441433 is a wasteful number, since it uses less digits than its factorization.

12132441433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1189407.

The product of its digits is 6912, while the sum is 28.

Adding to 12132441433 its reverse (33414423121), we get a palindrome (45546864554).

The spelling of 12132441433 in words is "twelve billion, one hundred thirty-two million, four hundred forty-one thousand, four hundred thirty-three".

Divisors: 1 7 1459 10213 1187941 8315587 1733205919 12132441433