12133000033121 has 4 divisors (see below), whose sum is σ = 13236000036144. Its totient is φ = 11030000030100.

The previous prime is 12133000033097. The next prime is 12133000033129.

12133000033121 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12133000033121 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12133000033093 and 12133000033102.

It is not an unprimeable number, because it can be changed into a prime (12133000033129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 551500001495 + ... + 551500001516.

It is an arithmetic number, because the mean of its divisors is an integer number (3309000009036).

Almost surely, 2^{12133000033121} is an apocalyptic number.

12133000033121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

12133000033121 is a deficient number, since it is larger than the sum of its proper divisors (1103000003023).

12133000033121 is a wasteful number, since it uses less digits than its factorization.

12133000033121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1103000003022.

The product of its (nonzero) digits is 324, while the sum is 20.

It can be divided in two parts, 121330000 and 33121, that added together give a palindrome (121363121).

The spelling of 12133000033121 in words is "twelve trillion, one hundred thirty-three billion, thirty-three thousand, one hundred twenty-one".