Base | Representation |
---|---|
bin | 11011100101100101011000… |
… | …111011011001110111000010 |
3 | 120220121000222220220121102112 |
4 | 123211211120323121313002 |
5 | 111400332341404042010 |
6 | 1110014124304015322 |
7 | 34361543036124650 |
oct | 3345453073316702 |
9 | 526530886817375 |
10 | 121330023112130 |
11 | 35728856a85968 |
12 | 117366a3301542 |
13 | 52914ab61c001 |
14 | 21d6593b5bdd0 |
15 | e0611421ca05 |
hex | 6e5958ed9dc2 |
121330023112130 has 64 divisors (see below), whose sum is σ = 254068677492480. Its totient is φ = 40855013971200.
The previous prime is 121330023112097. The next prime is 121330023112183. The reversal of 121330023112130 is 31211320033121.
It is a junction number, because it is equal to n+sod(n) for n = 121330023112096 and 121330023112105.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 18671120 + ... + 24316059.
It is an arithmetic number, because the mean of its divisors is an integer number (3969823085820).
Almost surely, 2121330023112130 is an apocalyptic number.
121330023112130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
121330023112130 is an abundant number, since it is smaller than the sum of its proper divisors (132738654380350).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121330023112130 is a wasteful number, since it uses less digits than its factorization.
121330023112130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42987915.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 121330023112130 its reverse (31211320033121), we get a palindrome (152541343145251).
The spelling of 121330023112130 in words is "one hundred twenty-one trillion, three hundred thirty billion, twenty-three million, one hundred twelve thousand, one hundred thirty".
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