Base | Representation |
---|---|
bin | 1011000010001111000001… |
… | …0111011100011000011111 |
3 | 1120221220110001021120100112 |
4 | 2300203300113130120133 |
5 | 3042241411200240221 |
6 | 41445455501120235 |
7 | 2361403361050241 |
oct | 260436027343037 |
9 | 46856401246315 |
10 | 12133020321311 |
11 | 395864873404a |
12 | 143b563b5907b |
13 | 6a01a6242396 |
14 | 2dd354260091 |
15 | 16091aede15b |
hex | b08f05dc61f |
12133020321311 has 2 divisors, whose sum is σ = 12133020321312. Its totient is φ = 12133020321310.
The previous prime is 12133020321283. The next prime is 12133020321329. The reversal of 12133020321311 is 11312302033121.
12133020321311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12133020321311 - 234 = 12115840452127 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12133020321391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6066510160655 + 6066510160656.
It is an arithmetic number, because the mean of its divisors is an integer number (6066510160656).
Almost surely, 212133020321311 is an apocalyptic number.
12133020321311 is a deficient number, since it is larger than the sum of its proper divisors (1).
12133020321311 is an equidigital number, since it uses as much as digits as its factorization.
12133020321311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 12133020321311 its reverse (11312302033121), we get a palindrome (23445322354432).
The spelling of 12133020321311 in words is "twelve trillion, one hundred thirty-three billion, twenty million, three hundred twenty-one thousand, three hundred eleven".
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