Base | Representation |
---|---|
bin | 10110100110011001… |
… | …10101111010100111 |
3 | 1011022120221011222110 |
4 | 23103030311322213 |
5 | 144322110344420 |
6 | 5323550332103 |
7 | 606450203133 |
oct | 132314657247 |
9 | 34276834873 |
10 | 12133293735 |
11 | 5166a23192 |
12 | 24274ba033 |
13 | 11b4964564 |
14 | 8315d83c3 |
15 | 4b02eeee0 |
hex | 2d3335ea7 |
12133293735 has 8 divisors (see below), whose sum is σ = 19413270000. Its totient is φ = 6471089984.
The previous prime is 12133293677. The next prime is 12133293769. The reversal of 12133293735 is 53739233121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12133293735 - 215 = 12133260967 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12133293693 and 12133293702.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 404443110 + ... + 404443139.
It is an arithmetic number, because the mean of its divisors is an integer number (2426658750).
Almost surely, 212133293735 is an apocalyptic number.
12133293735 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12133293735 is a deficient number, since it is larger than the sum of its proper divisors (7279976265).
12133293735 is an equidigital number, since it uses as much as digits as its factorization.
12133293735 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 808886257.
The product of its digits is 102060, while the sum is 39.
The spelling of 12133293735 in words is "twelve billion, one hundred thirty-three million, two hundred ninety-three thousand, seven hundred thirty-five".
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