Base | Representation |
---|---|
bin | 10001101010000000000… |
… | …111110100100010000110 |
3 | 11021222211002001002100212 |
4 | 101222000013310202012 |
5 | 124334400024430202 |
6 | 2325221331235422 |
7 | 153442312323254 |
oct | 21520007644206 |
9 | 4258732032325 |
10 | 1213330311302 |
11 | 42863036929a |
12 | 177199a48b72 |
13 | 8a55523b085 |
14 | 42a22ab75d4 |
15 | 21865137652 |
hex | 11a801f4886 |
1213330311302 has 4 divisors (see below), whose sum is σ = 1819995466956. Its totient is φ = 606665155650.
The previous prime is 1213330311293. The next prime is 1213330311371. The reversal of 1213330311302 is 2031130333121.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 303332577824 + ... + 303332577827.
It is an arithmetic number, because the mean of its divisors is an integer number (454998866739).
Almost surely, 21213330311302 is an apocalyptic number.
1213330311302 is a deficient number, since it is larger than the sum of its proper divisors (606665155654).
1213330311302 is an equidigital number, since it uses as much as digits as its factorization.
1213330311302 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 606665155653.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 1213330311302 its reverse (2031130333121), we get a palindrome (3244460644423).
The spelling of 1213330311302 in words is "one trillion, two hundred thirteen billion, three hundred thirty million, three hundred eleven thousand, three hundred two".
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