12133303120130 has 8 divisors (see below), whose sum is σ = 21839945616252. Its totient is φ = 4853321248048.

The previous prime is 12133303120123. The next prime is 12133303120139. The reversal of 12133303120130 is 3102130333121.

It can be written as a sum of positive squares in 2 ways, for example, as 12091065882841 + 42237237289 = 3477221^2 + 205517^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×12133303120130² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12133303120096 and 12133303120105.

It is not an unprimeable number, because it can be changed into a prime (12133303120139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 606665155997 + ... + 606665156016.

Almost surely, 2^{12133303120130} is an apocalyptic number.

12133303120130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

12133303120130 is a deficient number, since it is larger than the sum of its proper divisors (9706642496122).

12133303120130 is a wasteful number, since it uses less digits than its factorization.

12133303120130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1213330312020.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 12133303120130 its reverse (3102130333121), we get a palindrome (15235433453251).

The spelling of 12133303120130 in words is "twelve trillion, one hundred thirty-three billion, three hundred three million, one hundred twenty thousand, one hundred thirty".