Base | Representation |
---|---|
bin | 10001101010000000001… |
… | …010111101001110100001 |
3 | 11021222211010120211222220 |
4 | 101222000022331032201 |
5 | 124334400232231340 |
6 | 2325221401021253 |
7 | 153442322316012 |
oct | 21520012751641 |
9 | 4258733524886 |
10 | 1213331133345 |
11 | 42863087a971 |
12 | 17719a184829 |
13 | 8a5554682a6 |
14 | 42a22c4d009 |
15 | 2186524aed0 |
hex | 11a802bd3a1 |
1213331133345 has 16 divisors (see below), whose sum is σ = 1961343525120. Its totient is φ = 640438700544.
The previous prime is 1213331133299. The next prime is 1213331133347. The reversal of 1213331133345 is 5433311333121.
It is a happy number.
It is not a de Polignac number, because 1213331133345 - 212 = 1213331129249 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1213331133347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 416950825 + ... + 416953734.
It is an arithmetic number, because the mean of its divisors is an integer number (122583970320).
Almost surely, 21213331133345 is an apocalyptic number.
1213331133345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1213331133345 is a deficient number, since it is larger than the sum of its proper divisors (748012391775).
1213331133345 is an equidigital number, since it uses as much as digits as its factorization.
1213331133345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 833904664.
The product of its digits is 29160, while the sum is 33.
Adding to 1213331133345 its reverse (5433311333121), we get a palindrome (6646642466466).
The spelling of 1213331133345 in words is "one trillion, two hundred thirteen billion, three hundred thirty-one million, one hundred thirty-three thousand, three hundred forty-five".
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