Base | Representation |
---|---|
bin | 11011100101101000010001… |
… | …101001100010000101101011 |
3 | 120220121022222220102012111201 |
4 | 123211220101221202011223 |
5 | 111400410213241242303 |
6 | 1110015400012305031 |
7 | 34362012610054066 |
oct | 3345502151420553 |
9 | 526538886365451 |
10 | 121333122212203 |
11 | 3572a0a73826a0 |
12 | 11737209172177 |
13 | 52918836c0535 |
14 | 21d67a959d8dd |
15 | e0624633981d |
hex | 6e5a11a6216b |
121333122212203 has 64 divisors (see below), whose sum is σ = 143561213706240. Its totient is φ = 101431782812800.
The previous prime is 121333122212161. The next prime is 121333122212279. The reversal of 121333122212203 is 302212221333121.
It is a de Polignac number, because none of the positive numbers 2k-121333122212203 is a prime.
It is a super-2 number, since 2×1213331222122032 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (121333122212903) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 895835898 + ... + 895971328.
It is an arithmetic number, because the mean of its divisors is an integer number (2243143964160).
Almost surely, 2121333122212203 is an apocalyptic number.
121333122212203 is a deficient number, since it is larger than the sum of its proper divisors (22228091494037).
121333122212203 is a wasteful number, since it uses less digits than its factorization.
121333122212203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 136848.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 121333122212203 its reverse (302212221333121), we get a palindrome (423545343545324).
The spelling of 121333122212203 in words is "one hundred twenty-one trillion, three hundred thirty-three billion, one hundred twenty-two million, two hundred twelve thousand, two hundred three".
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