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121335438689 is a prime number
BaseRepresentation
bin111000100000000100…
…1111101110101100001
3102121012002000220222122
41301000021331311201
53441443333014224
6131423555314025
711523543132443
oct1610011756541
9377162026878
10121335438689
1147504767a63
121b622bab915
13b598a7c98a
145c30850493
15325234615e
hex1c4027dd61

121335438689 has 2 divisors, whose sum is σ = 121335438690. Its totient is φ = 121335438688.

The previous prime is 121335438683. The next prime is 121335438739. The reversal of 121335438689 is 986834533121.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 120674948689 + 660490000 = 347383^2 + 25700^2 .

It is a cyclic number.

It is not a de Polignac number, because 121335438689 - 236 = 52615961953 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 121335438689.

It is not a weakly prime, because it can be changed into another prime (121335438683) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60667719344 + 60667719345.

It is an arithmetic number, because the mean of its divisors is an integer number (60667719345).

Almost surely, 2121335438689 is an apocalyptic number.

It is an amenable number.

121335438689 is a deficient number, since it is larger than the sum of its proper divisors (1).

121335438689 is an equidigital number, since it uses as much as digits as its factorization.

121335438689 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3732480, while the sum is 53.

The spelling of 121335438689 in words is "one hundred twenty-one billion, three hundred thirty-five million, four hundred thirty-eight thousand, six hundred eighty-nine".