12134014253131 has 4 divisors (see below), whose sum is σ = 12226640316264. Its totient is φ = 12041388190000.

The previous prime is 12134014253069. The next prime is 12134014253143. The reversal of 12134014253131 is 13135241043121.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12134014253131 - 2²³ = 12134005864523 is a prime.

It is a super-2 number, since 2×12134014253131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12134014253093 and 12134014253102.

It is not an unprimeable number, because it can be changed into a prime (12134014251131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46313031370 + ... + 46313031631.

It is an arithmetic number, because the mean of its divisors is an integer number (3056660079066).

Almost surely, 2^{12134014253131} is an apocalyptic number.

12134014253131 is a deficient number, since it is larger than the sum of its proper divisors (92626063133).

12134014253131 is an equidigital number, since it uses as much as digits as its factorization.

12134014253131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92626063132.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 12134014253131 its reverse (13135241043121), we get a palindrome (25269255296252).

The spelling of 12134014253131 in words is "twelve trillion, one hundred thirty-four billion, fourteen million, two hundred fifty-three thousand, one hundred thirty-one".