Base | Representation |
---|---|
bin | 10001101010000101001… |
… | …000011000010111011001 |
3 | 11022000000221011101202200 |
4 | 101222011020120113121 |
5 | 124340033033003103 |
6 | 2325233532320413 |
7 | 153444352514064 |
oct | 21520510302731 |
9 | 4260027141680 |
10 | 1213414344153 |
11 | 428673844430 |
12 | 177202013109 |
13 | 8a569780c5b |
14 | 42a2dd0d8db |
15 | 2186c6d60a3 |
hex | 11a852185d9 |
1213414344153 has 48 divisors (see below), whose sum is σ = 1924663021632. Its totient is φ = 730566144000.
The previous prime is 1213414344143. The next prime is 1213414344157. The reversal of 1213414344153 is 3514434143121.
1213414344153 is a `hidden beast` number, since 1 + 2 + 134 + 1 + 434 + 41 + 53 = 666.
It is not a de Polignac number, because 1213414344153 - 26 = 1213414344089 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1213414344157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 9142201 + ... + 9273977.
It is an arithmetic number, because the mean of its divisors is an integer number (40097146284).
Almost surely, 21213414344153 is an apocalyptic number.
It is an amenable number.
1213414344153 is a deficient number, since it is larger than the sum of its proper divisors (711248677479).
1213414344153 is a wasteful number, since it uses less digits than its factorization.
1213414344153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 132406 (or 132403 counting only the distinct ones).
The product of its digits is 69120, while the sum is 36.
Adding to 1213414344153 its reverse (3514434143121), we get a palindrome (4727848487274).
The spelling of 1213414344153 in words is "one trillion, two hundred thirteen billion, four hundred fourteen million, three hundred forty-four thousand, one hundred fifty-three".
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