Base | Representation |
---|---|
bin | 10001101010000110001… |
… | …111111011111011011100 |
3 | 11022000002020110101202101 |
4 | 101222012033323323130 |
5 | 124340102333231134 |
6 | 2325235442334444 |
7 | 153445001120602 |
oct | 21520617737334 |
9 | 4260066411671 |
10 | 1213433102044 |
11 | 428683396519 |
12 | 17720835a424 |
13 | 8a57061abb7 |
14 | 42a325d3872 |
15 | 2186e18de14 |
hex | 11a863fbedc |
1213433102044 has 12 divisors (see below), whose sum is σ = 2123632659568. Its totient is φ = 606680913600.
The previous prime is 1213433102023. The next prime is 1213433102087. The reversal of 1213433102044 is 4402013343121.
It is a happy number.
It is a super-2 number, since 2×12134331020442 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8832672 + ... + 8968999.
Almost surely, 21213433102044 is an apocalyptic number.
It is an amenable number.
1213433102044 is a deficient number, since it is larger than the sum of its proper divisors (910199557524).
1213433102044 is a wasteful number, since it uses less digits than its factorization.
1213433102044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17818716 (or 17818714 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 1213433102044 its reverse (4402013343121), we get a palindrome (5615446445165).
The spelling of 1213433102044 in words is "one trillion, two hundred thirteen billion, four hundred thirty-three million, one hundred two thousand, forty-four".
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