121345005333 has 4 divisors (see below), whose sum is σ = 161793340448. Its totient is φ = 80896670220.

The previous prime is 121345005329. The next prime is 121345005349. The reversal of 121345005333 is 333500543121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 121345005333 - 2² = 121345005329 is a prime.

It is a super-3 number, since 3×121345005333³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 121345005333.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121345005323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20224167553 + ... + 20224167558.

It is an arithmetic number, because the mean of its divisors is an integer number (40448335112).

Almost surely, 2^121345005333 is an apocalyptic number.

It is an amenable number.

121345005333 is a deficient number, since it is larger than the sum of its proper divisors (40448335115).

121345005333 is an equidigital number, since it uses as much as digits as its factorization.

121345005333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40448335114.

The product of its (nonzero) digits is 16200, while the sum is 30.

Adding to 121345005333 its reverse (333500543121), we get a palindrome (454845548454).

The spelling of 121345005333 in words is "one hundred twenty-one billion, three hundred forty-five million, five thousand, three hundred thirty-three".