Base | Representation |
---|---|
bin | 111000100000100011… |
… | …1010110101000011101 |
3 | 102121020012022111112112 |
4 | 1301001013112220131 |
5 | 3442011442443122 |
6 | 131425332243405 |
7 | 11524126665062 |
oct | 1610107265035 |
9 | 377205274475 |
10 | 121351531037 |
11 | 47512859420 |
12 | 1b628470565 |
13 | b59c1c5589 |
14 | 5c32a3cc69 |
15 | 32539742e2 |
hex | 1c411d6a1d |
121351531037 has 32 divisors (see below), whose sum is σ = 141215114880. Its totient is φ = 103245425920.
The previous prime is 121351530953. The next prime is 121351531051. The reversal of 121351531037 is 730135153121.
It is a cyclic number.
It is not a de Polignac number, because 121351531037 - 218 = 121351268893 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121351530994 and 121351531012.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121351531237) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1360043 + ... + 1446519.
It is an arithmetic number, because the mean of its divisors is an integer number (4412972340).
Almost surely, 2121351531037 is an apocalyptic number.
It is an amenable number.
121351531037 is a deficient number, since it is larger than the sum of its proper divisors (19863583843).
121351531037 is a wasteful number, since it uses less digits than its factorization.
121351531037 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 86653.
The product of its (nonzero) digits is 9450, while the sum is 32.
Adding to 121351531037 its reverse (730135153121), we get a palindrome (851486684158).
The spelling of 121351531037 in words is "one hundred twenty-one billion, three hundred fifty-one million, five hundred thirty-one thousand, thirty-seven".
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