Base | Representation |
---|---|
bin | 10001101010001100000… |
… | …111011001000000011111 |
3 | 11022000100002122210212122 |
4 | 101222030013121000133 |
5 | 124340303032301101 |
6 | 2325253320053155 |
7 | 153450304524461 |
oct | 21521407310037 |
9 | 4260302583778 |
10 | 1213531525151 |
11 | 428723a00230 |
12 | 1772353041bb |
13 | 8a587b2ba1a |
14 | 42a416d4131 |
15 | 21877b3151b |
hex | 11a8c1d901f |
1213531525151 has 4 divisors (see below), whose sum is σ = 1323852572904. Its totient is φ = 1103210477400.
The previous prime is 1213531525127. The next prime is 1213531525159. The reversal of 1213531525151 is 1515251353121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1213531525151 - 226 = 1213464416287 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1213531525159) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55160523860 + ... + 55160523881.
It is an arithmetic number, because the mean of its divisors is an integer number (330963143226).
Almost surely, 21213531525151 is an apocalyptic number.
1213531525151 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1213531525151 is a deficient number, since it is larger than the sum of its proper divisors (110321047753).
1213531525151 is a wasteful number, since it uses less digits than its factorization.
1213531525151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110321047752.
The product of its digits is 22500, while the sum is 35.
Adding to 1213531525151 its reverse (1515251353121), we get a palindrome (2728782878272).
The spelling of 1213531525151 in words is "one trillion, two hundred thirteen billion, five hundred thirty-one million, five hundred twenty-five thousand, one hundred fifty-one".
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