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1214001343343 = 5872068145389
BaseRepresentation
bin10001101010101000000…
…111100110101101101111
311022001112211201001021102
4101222220013212231233
5124342233320441333
62325412101553315
7153465041105015
oct21525007465557
94261484631242
101214001343343
11428945122628
1217734671583b
138a631277159
1442a87c708b5
15218a3ed6ae8
hex11aa81e6b6f

1214001343343 has 4 divisors (see below), whose sum is σ = 1216069489320. Its totient is φ = 1211933197368.

The previous prime is 1214001343309. The next prime is 1214001343349. The reversal of 1214001343343 is 3433431004121.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1214001343343 - 210 = 1214001342319 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1214001343349) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1034072108 + ... + 1034073281.

It is an arithmetic number, because the mean of its divisors is an integer number (304017372330).

Almost surely, 21214001343343 is an apocalyptic number.

1214001343343 is a deficient number, since it is larger than the sum of its proper divisors (2068145977).

1214001343343 is an equidigital number, since it uses as much as digits as its factorization.

1214001343343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2068145976.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 1214001343343 its reverse (3433431004121), we get a palindrome (4647432347464).

The spelling of 1214001343343 in words is "one trillion, two hundred fourteen billion, one million, three hundred forty-three thousand, three hundred forty-three".

Divisors: 1 587 2068145389 1214001343343