1214013402101 has 4 divisors (see below), whose sum is σ = 1214019069600. Its totient is φ = 1214007734604.

The previous prime is 1214013402097. The next prime is 1214013402109. The reversal of 1214013402101 is 1012043104121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1214013402101 - 2² = 1214013402097 is a prime.

It is a super-2 number, since 2×1214013402101² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1214013402109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2499281 + ... + 2945238.

It is an arithmetic number, because the mean of its divisors is an integer number (303504767400).

Almost surely, 2^{1214013402101} is an apocalyptic number.

It is an amenable number.

1214013402101 is a deficient number, since it is larger than the sum of its proper divisors (5667499).

1214013402101 is an equidigital number, since it uses as much as digits as its factorization.

1214013402101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5667498.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 1214013402101 its reverse (1012043104121), we get a palindrome (2226056506222).

The spelling of 1214013402101 in words is "one trillion, two hundred fourteen billion, thirteen million, four hundred two thousand, one hundred one".