1214111214041 has 4 divisors (see below), whose sum is σ = 1324484960784. Its totient is φ = 1103737467300.

The previous prime is 1214111214007. The next prime is 1214111214067. The reversal of 1214111214041 is 1404121114121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1214111214041 - 2⁶ = 1214111213977 is a prime.

It is a super-2 number, since 2×1214111214041² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1214111213998 and 1214111214016.

It is not an unprimeable number, because it can be changed into a prime (1214111214941) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55186873355 + ... + 55186873376.

It is an arithmetic number, because the mean of its divisors is an integer number (331121240196).

Almost surely, 2^{1214111214041} is an apocalyptic number.

1214111214041 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1214111214041 is a deficient number, since it is larger than the sum of its proper divisors (110373746743).

1214111214041 is a wasteful number, since it uses less digits than its factorization.

1214111214041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110373746742.

The product of its (nonzero) digits is 256, while the sum is 23.

Adding to 1214111214041 its reverse (1404121114121), we get a palindrome (2618232328162).

The spelling of 1214111214041 in words is "one trillion, two hundred fourteen billion, one hundred eleven million, two hundred fourteen thousand, forty-one".