Base | Representation |
---|---|
bin | 10001101010101111010… |
… | …001101101001111010111 |
3 | 11022001212012200011222022 |
4 | 101222233101231033113 |
5 | 124343010041311043 |
6 | 2325432031523355 |
7 | 153501026615543 |
oct | 21525721551727 |
9 | 4261765604868 |
10 | 1214121432023 |
11 | 4289a6994a75 |
12 | 17737a98955b |
13 | 8a650102546 |
14 | 42a99bb0a23 |
15 | 218ae808868 |
hex | 11aaf46d3d7 |
1214121432023 has 2 divisors, whose sum is σ = 1214121432024. Its totient is φ = 1214121432022.
The previous prime is 1214121432011. The next prime is 1214121432031. The reversal of 1214121432023 is 3202341214121.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1214121432023 - 210 = 1214121430999 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1214121431983 and 1214121432001.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1214121632023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607060716011 + 607060716012.
It is an arithmetic number, because the mean of its divisors is an integer number (607060716012).
Almost surely, 21214121432023 is an apocalyptic number.
1214121432023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1214121432023 is an equidigital number, since it uses as much as digits as its factorization.
1214121432023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 1214121432023 its reverse (3202341214121), we get a palindrome (4416462646144).
The spelling of 1214121432023 in words is "one trillion, two hundred fourteen billion, one hundred twenty-one million, four hundred thirty-two thousand, twenty-three".
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