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12141300002243 = 17714194117779
BaseRepresentation
bin1011000010101101110111…
…0111111010110111000011
31120222200211001221221100212
42300223131313322313003
53042410340300032433
641453345231304335
72362115506141556
oct260533567726703
946880731857325
1012141300002243
113961107367965
12144109497b0ab
136a0bc56ba879
142dd8dbb2c69d
15160c52d32d48
hexb0adddfadc3

12141300002243 has 4 divisors (see below), whose sum is σ = 12855494120040. Its totient is φ = 11427105884448.

The previous prime is 12141300002233. The next prime is 12141300002257. The reversal of 12141300002243 is 34220000314121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12141300002243 - 226 = 12141232893379 is a prime.

It is a super-3 number, since 3×121413000022433 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12141300002233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 357097058873 + ... + 357097058906.

It is an arithmetic number, because the mean of its divisors is an integer number (3213873530010).

Almost surely, 212141300002243 is an apocalyptic number.

12141300002243 is a deficient number, since it is larger than the sum of its proper divisors (714194117797).

12141300002243 is an equidigital number, since it uses as much as digits as its factorization.

12141300002243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 714194117796.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 12141300002243 its reverse (34220000314121), we get a palindrome (46361300316364).

The spelling of 12141300002243 in words is "twelve trillion, one hundred forty-one billion, three hundred million, two thousand, two hundred forty-three".

Divisors: 1 17 714194117779 12141300002243