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1214143230351 = 31071373777541
BaseRepresentation
bin10001101010110000100…
…100110111000110001111
311022001220201200122122210
4101222300210313012033
5124343031131332401
62325434131041503
7153501413114532
oct21526044670617
94261821618583
101214143230351
11428a08223417
12177386140293
138a65479536c
1442a9ca46a19
15218b16b24d6
hex11ab093718f

1214143230351 has 8 divisors (see below), whose sum is σ = 1618873179184. Its totient is φ = 809421050880.

The previous prime is 1214143230319. The next prime is 1214143230373. The reversal of 1214143230351 is 1530323414121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1214143230351 - 25 = 1214143230319 is a prime.

It is a super-2 number, since 2×12141432303512 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1214143235351) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1567360 + ... + 2210181.

It is an arithmetic number, because the mean of its divisors is an integer number (202359147398).

Almost surely, 21214143230351 is an apocalyptic number.

1214143230351 is a deficient number, since it is larger than the sum of its proper divisors (404729948833).

1214143230351 is a wasteful number, since it uses less digits than its factorization.

1214143230351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3884681.

The product of its (nonzero) digits is 8640, while the sum is 30.

Adding to 1214143230351 its reverse (1530323414121), we get a palindrome (2744466644472).

The spelling of 1214143230351 in words is "one trillion, two hundred fourteen billion, one hundred forty-three million, two hundred thirty thousand, three hundred fifty-one".

Divisors: 1 3 107137 321411 3777541 11332623 404714410117 1214143230351