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1214224321151 is a prime number
BaseRepresentation
bin10001101010110101011…
…010001100101001111111
311022002010101021111022202
4101222311122030221333
5124343212411234101
62325450145102115
7153503416303052
oct21526532145177
94262111244282
101214224321151
11428a49a7a106
121773a932793b
138a66851809a
1442aa9714a99
15218b887e36b
hex11ab568ca7f

1214224321151 has 2 divisors, whose sum is σ = 1214224321152. Its totient is φ = 1214224321150.

The previous prime is 1214224321129. The next prime is 1214224321157. The reversal of 1214224321151 is 1511234224121.

It is a strong prime.

It is an emirp because it is prime and its reverse (1511234224121) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1214224321151 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1214224321157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 607112160575 + 607112160576.

It is an arithmetic number, because the mean of its divisors is an integer number (607112160576).

Almost surely, 21214224321151 is an apocalyptic number.

1214224321151 is a deficient number, since it is larger than the sum of its proper divisors (1).

1214224321151 is an equidigital number, since it uses as much as digits as its factorization.

1214224321151 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3840, while the sum is 29.

Adding to 1214224321151 its reverse (1511234224121), we get a palindrome (2725458545272).

The spelling of 1214224321151 in words is "one trillion, two hundred fourteen billion, two hundred twenty-four million, three hundred twenty-one thousand, one hundred fifty-one".