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12142665388870 = 251214266538887
BaseRepresentation
bin1011000010110010111101…
…0000011101001101000110
31120222211100020011202200221
42300230233100131031012
53042421134314420440
641454132524254554
72362164365552602
oct260545720351506
946884306152627
1012142665388870
113961748065065
1214413b60a145a
136a108253a553
142dd9cb1d0502
15160cd2b3bd4a
hexb0b2f41d346

12142665388870 has 8 divisors (see below), whose sum is σ = 21856797699984. Its totient is φ = 4857066155544.

The previous prime is 12142665388813. The next prime is 12142665388883. The reversal of 12142665388870 is 7888356624121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×121426653888703 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 12142665388799 and 12142665388808.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 607133269434 + ... + 607133269453.

It is an arithmetic number, because the mean of its divisors is an integer number (2732099712498).

Almost surely, 212142665388870 is an apocalyptic number.

12142665388870 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

12142665388870 is a deficient number, since it is larger than the sum of its proper divisors (9714132311114).

12142665388870 is a wasteful number, since it uses less digits than its factorization.

12142665388870 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1214266538894.

The product of its (nonzero) digits is 30965760, while the sum is 61.

The spelling of 12142665388870 in words is "twelve trillion, one hundred forty-two billion, six hundred sixty-five million, three hundred eighty-eight thousand, eight hundred seventy".

Divisors: 1 2 5 10 1214266538887 2428533077774 6071332694435 12142665388870