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12143023411301 is a prime number
BaseRepresentation
bin1011000010110100010010…
…0110001101000001100101
31120222212021011212012010222
42300231010212031001211
53042422402443130201
641454232234054125
72362206303652016
oct260550446150145
946885234765128
1012143023411301
113961911169672
121441495b7a345
136a110b772143
142dda2298900d
15160d042ac91b
hexb0b4498d065

12143023411301 has 2 divisors, whose sum is σ = 12143023411302. Its totient is φ = 12143023411300.

The previous prime is 12143023411279. The next prime is 12143023411319. The reversal of 12143023411301 is 10311432034121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11239430580676 + 903592830625 = 3352526^2 + 950575^2 .

It is a cyclic number.

It is not a de Polignac number, because 12143023411301 - 218 = 12143023149157 is a prime.

It is a super-3 number, since 3×121430234113013 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12143023411201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6071511705650 + 6071511705651.

It is an arithmetic number, because the mean of its divisors is an integer number (6071511705651).

Almost surely, 212143023411301 is an apocalyptic number.

It is an amenable number.

12143023411301 is a deficient number, since it is larger than the sum of its proper divisors (1).

12143023411301 is an equidigital number, since it uses as much as digits as its factorization.

12143023411301 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 12143023411301 its reverse (10311432034121), we get a palindrome (22454455445422).

The spelling of 12143023411301 in words is "twelve trillion, one hundred forty-three billion, twenty-three million, four hundred eleven thousand, three hundred one".