Base | Representation |
---|---|
bin | 1011000010110100010010… |
… | …0110001101000001110111 |
3 | 1120222212021011212012011122 |
4 | 2300231010212031001313 |
5 | 3042422402443130234 |
6 | 41454232234054155 |
7 | 2362206303652043 |
oct | 260550446150167 |
9 | 46885234765148 |
10 | 12143023411319 |
11 | 3961911169689 |
12 | 1441495b7a35b |
13 | 6a110b772158 |
14 | 2dda22989023 |
15 | 160d042ac92e |
hex | b0b4498d077 |
12143023411319 has 2 divisors, whose sum is σ = 12143023411320. Its totient is φ = 12143023411318.
The previous prime is 12143023411301. The next prime is 12143023411357. The reversal of 12143023411319 is 91311432034121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12143023411319 - 232 = 12138728444023 is a prime.
It is a super-3 number, since 3×121430234113193 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12143023411399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6071511705659 + 6071511705660.
It is an arithmetic number, because the mean of its divisors is an integer number (6071511705660).
Almost surely, 212143023411319 is an apocalyptic number.
12143023411319 is a deficient number, since it is larger than the sum of its proper divisors (1).
12143023411319 is an equidigital number, since it uses as much as digits as its factorization.
12143023411319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 35.
The spelling of 12143023411319 in words is "twelve trillion, one hundred forty-three billion, twenty-three million, four hundred eleven thousand, three hundred nineteen".
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