Base | Representation |
---|---|
bin | 10001101010111010101… |
… | …110000101011010100111 |
3 | 11022002100120221012120222 |
4 | 101222322232011122213 |
5 | 124343403213423310 |
6 | 2325503050514555 |
7 | 153505550524562 |
oct | 21527256053247 |
9 | 4262316835528 |
10 | 1214313420455 |
11 | 428a952a57a3 |
12 | 177413135a5b |
13 | 8a680b13075 |
14 | 42ab74a94d9 |
15 | 218c15ce055 |
hex | 11abab856a7 |
1214313420455 has 8 divisors (see below), whose sum is σ = 1464572938752. Its totient is φ = 966519513568.
The previous prime is 1214313420427. The next prime is 1214313420497. The reversal of 1214313420455 is 5540243134121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1214313420455 - 214 = 1214313404071 is a prime.
It is a super-2 number, since 2×12143134204552 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 616401767 + ... + 616403736.
It is an arithmetic number, because the mean of its divisors is an integer number (183071617344).
Almost surely, 21214313420455 is an apocalyptic number.
1214313420455 is a deficient number, since it is larger than the sum of its proper divisors (250259518297).
1214313420455 is a wasteful number, since it uses less digits than its factorization.
1214313420455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1232805705.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 1214313420455 its reverse (5540243134121), we get a palindrome (6754556554576).
The spelling of 1214313420455 in words is "one trillion, two hundred fourteen billion, three hundred thirteen million, four hundred twenty thousand, four hundred fifty-five".
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