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121433334133 is a prime number
BaseRepresentation
bin111000100010111111…
…1011010000101110101
3102121102220020112021211
41301011333122011311
53442143413143013
6131441413441421
711526142211056
oct1610577320565
9377386215254
10121433334133
1147554a51291
121b64b940271
13b5b3137587
145c3d85472d
15325ac3223d
hex1c45fda175

121433334133 has 2 divisors, whose sum is σ = 121433334134. Its totient is φ = 121433334132.

The previous prime is 121433334131. The next prime is 121433334157. The reversal of 121433334133 is 331433334121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 94250228004 + 27183106129 = 307002^2 + 164873^2 .

It is an emirp because it is prime and its reverse (331433334121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121433334133 - 21 = 121433334131 is a prime.

Together with 121433334131, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 121433334095 and 121433334104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121433334131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60716667066 + 60716667067.

It is an arithmetic number, because the mean of its divisors is an integer number (60716667067).

Almost surely, 2121433334133 is an apocalyptic number.

It is an amenable number.

121433334133 is a deficient number, since it is larger than the sum of its proper divisors (1).

121433334133 is an equidigital number, since it uses as much as digits as its factorization.

121433334133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 23328, while the sum is 31.

Adding to 121433334133 its reverse (331433334121), we get a palindrome (452866668254).

The spelling of 121433334133 in words is "one hundred twenty-one billion, four hundred thirty-three million, three hundred thirty-four thousand, one hundred thirty-three".